Please describe in detail how one would balance for an oxidation-reduction chemistry problem such as this:
MnO4-(aq) + S2-(aq) 鈫?MnS(s) + S(s)
"4" represents the number of oxygen atoms, "-" represents the charge of the MnO4- molecule, and "2-" represents the charge of the sulfur. I know there are supposed to be two equations but I am not sure how to set them up and solve. Thank you for your time.|||I believe your chemical rxn is incorrect because you have lost 4 oxygen atoms and don't account for them in your products, but the way to solving a oxidation reduction rxn is to remember the simple saying oil rig oxidation is loss and reduction is gain. so you would examine which species has lost electrons and how many and which as gained and how many..
Hope that helps, sorry i couldn't give you exact #'s but i would look at your rxn i am sure something isn't right
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